A passenger told an air hostess that he needed a cup of water to take his medicine whe - 希财猫问答

第1题

A passenger told an air hostess that he needed a cup of water to take his medicine when

the plane just took off. She told him that she would bring him the water in ten minutes.

The air hostess was kept so busy that she forgot to give him the water. As a result, the passenger was held up to take his medicine. Thirty minutes later, when the passenger's ring for service sounded, she hurried over to him with a cup of water, but he refused.

In the following hours on the plane, each time the air hostess passed by the passenger, she would ask him with a smile whether he needed help or not. But the passenger never answered a word.

When he was going to get off the plane, the passenger asked the air hostess to hand him the passengers' booklet. She was very sad. She knew that he would write down sharp words, but with a smile she handed it to him.

Off the plane, she opened the booklet, and smiled, for the passenger put it. “On the flight, you asked me whether I needed help or not for twelve times in all. How can I refuse your twelve sincere smiles？”

That's right! Who can refuse twelve sincere smiles from a person？

操作提示：句子正确选择下拉选项框为“T”;句子错误选择下拉选项框为“F”。

A passenger wants a cup of water because he is thirsty.

The air hostess forgot to give him the water on purpose.

The passenger refused the cup of water.

The passenger didn't write down any sharp words.

This passage tells us that a sincere smile is of no use.

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第2题

regular passenger flights

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第3题

Weight limitations on passenger baggage when you take a plane is，incidentally，for

the reason of making room for freight．（）

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第4题

The combination of numbers and letters like 15C on the boarding pass represents the passenger's seat number.（)

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第5题

In the short poem “Bloody men”, a woman waiting for the right man to turn up is compa

red to a passenger waiting for the right bus to come.()

此题为判断题(对，错)。

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第6题

What is the denomination of cash accepted by TVM when passenger pay for their ticket

s？()

A.10yuan

B.50yuan

C.20yuan

D.100yuan

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第7题

In the short poem “Bloody men”, a man waiting for his woman is not exactly like a pass

enger waiting for a bus.()

此题为判断题(对，错)。

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第8题

试题七（共 15 分）阅读下列说明、图和Java代码，将应填入（n）处的字句写在答题纸的对应栏内。 [说

试题七（共 15 分）

阅读下列说明、图和Java代码，将应填入（n）处的字句写在答题纸的对应栏内。

[说明]

已知对某载客车辆(Car)进行类建模，如图 7-1所示，其中类 Engine 表示发动机引擎，类 Wheel 表示车轮，类 Body 表示车身，类 Driver 表示司机，类 Passenger 表示乘客。

[Java 代码]

class Body{ //此处代码省略 }; //车身类

class Passenger{ //此处代码省略 }; //乘客类

class Wheel{ //此处代码省略 }; //车轮类

class Driver{ //司机类

public String name; //表示第几路公交车司机

public Driver(String driverName){name = driverName;} //构造函数

};

class Engine{ //引擎类

public String engineNo; //引擎编号

public Engine(String engineNo){ this.engineNo = engineNo; } //构造函数

};

public class Car{ //汽车类

static final int (1) = 7; //定义最多载客数

static final int MAX_WHEELS = 5; //定义最多轮胎数

protected Engine engine;

protected Driver driver;

protected Body body = new Body();

protected Wheel[] wheels;

protected Passenger[] passengers;

public Car(Driver driver){ //构造函数

(2) .driver = driver;

engine = new Engine("TX6536 型号引擎");

wheels = new Wheel[MAX_WHEELS];

passengers = new Passenger[MAX_PASSENGERS];

for (int index = 0; index ＜ MAX_WHEELS; index++){

wheels[index] = new Wheel();

}

for (int index = 0; index ＜ MAX_PASSENGERS; index++){

passengers[index] = null;

}

int getPassengerNumber(){ //获取车上乘客数量

//此处代码省略

}

void getOnPassenger(Passenger aPassenger ){ //乘客上车

//此处代码省略

}

void run(){ //开车

if((3) ){ System.out.println("司机尚未上车!"); return;}

//此处代码省略

}

public static void main(String args[]){

Driver driver = new Driver("第五路公交车司机");

Car car = new Car((4) );

for (int index = 0 ; index ＜ MAX_PASSENGERS; index ++)

car.getOnPassenger((5) Passenger());

car.run();

}

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第9题

阅读下列说明、图和Java代码，填补空缺。[说明] 已知对某载客车辆（Car)进行类建模，如图13－2所示，其

阅读下列说明、图和Java代码，填补空缺。

[说明]

已知对某载客车辆(Car)进行类建模，如图13-2所示，其中类Engine表示发动机引擎，类Wheel表示车轮，类Body表示车身，类Driver表示司机，类Passenger表示乘客。

[Java代码]

class Body{ //此处代码省略 }; //车身类

class Passenger{ //此处代码省略 }; //乘客类

class Wheel{ //此处代码省略 }; //车轮类

class Driver{ //司机类

public String name; //表示第几路公交车司机

public Driver(String driverName){name=driverName; }

//构造函数

};

class Engine{ //引擎类

public String engineNo; //引擎编号

public Engine(String engineNo){this.engineNo=engineNo; }

//构造函数

};

public class Car{ //汽车类

static final int (1) =7; //定义最多载客数

static final int MAX_WHEELS=5; //定义最多轮胎数

protected Engine engine;

protected Driver driver;

protected Body body=new Body();

protected Wheel[]wheels;

protected Passenger[]passengers;

public Car(Driver driver){ //构造函数

(2) .driver=driver;

engine=new Engine("TX6536型号引擎");

wheels = new Wheel[MAX_WHEELS];

passengers=new Passenger[MAX_PASSENGERS];

for(int index=0; index＜MAX_WHEELS; index++){

wheels[index]=new Wheel();

}

for(int index=0; index＜MAX_PASSENGERS; index++){

passengers[index]=null;

}

int getPassengerNumber(){ //获取车上乘客数量

//此处代码省略

}

void getOnPassenger(Passenger aPassenger ){

//乘客上车

//此处代码省略

}

void run(){ //开车

if((3) )(System.out.printin("司机尚未上车!"); return; }

//此处代码省略

}

public static void main(String args[]){

Driver driver=new Driver("第五路公交车司机");

Car car=new Car((4) );

for(int index=0; index ＜MAX_PASSENGERS; index++)

car.getOnPassenger((5) Passenger());

car.run();

}

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第10题

阅读下列说明、图和Java代码，将应填入（n)处的字句写在对应栏内。【说明】已知对某载客车辆（Car)进行

阅读下列说明、图和Java代码，将应填入(n)处的字句写在对应栏内。

【说明】

已知对某载客车辆(Car)进行类建模，如图7-1所示，其中类Engine表示发动机引擎，类Wheel表示车轮，类Body表示车身，类Driver表示司机，类Passenger表示乘客。

【Java代码】

class Body{ //此处代码省略 )； //车身类

class Passenger{ //此处代码省略 )/ //乘客类

class Wheel{ //此处代码省略 )； //车轮类

class Driver{ //司机类

public String name； //表示第几路公交车司机

public Driver(String driverName){name ＝ driverName/) //构造函数

}；

class Engine{//引擎类

public String engineNo；//引擎编号

public Engine(String engineNo){this．engineNo＝engineNo；)//构造函数

}；

public class Car{//汽车类

static final int(1)＝7； //定义最多载客数

static final int MAX WHEELS ＝5； //定义最多轮胎数

protected Engine engine；

protected Driver driver；

protected Body body＝new Body()；

protected Wheel[] wheels；

protected Passenger[]passengers；

public Car(Driver driver){ //构造函数

(2).driver＝driver；

engine＝new Engine("TX6536型号引擎")；

wheels＝new Wheel[MAX WHEELS]；

passengers＝new Passenger[MAX_PASSENGERS]；

for(int index＝0；index＜MAX_WHEELS；index++){

wheels[index]＝new Wheel()；

}

for(int index＝0；index＜MAX_PASSENGERS；index++){

passengers[index]＝null；

}

int getPassengerNumber(){//获取车上乘客数量

//此处代码省略

}

void getOnPassenger(Passenger aPassenger){//乘客上车

//此处代码省略

}

void run(){ //开车

if((3)){System.out.println("司机尚未上车!")；return；}

//此处代码省略

}

public static void main(String args[]){

Driver driver＝new Driver("第五路公交车司机")；

Car car＝new Car((4))；

for (int index ＝ 0 ； index ＜ MAX_PASSENGERS； index ++)

car．getOnPassenger((5) Passenger())；

car．run()；

}

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第11题

试题五（共 15 分）阅读下列说明、图和C＋＋代码，将应填入（n）处的字句写在答题纸的对应栏内。[说明]

试题五（共 15 分）

阅读下列说明、图和C++代码，将应填入（n）处的字句写在答题纸的对应栏内。

[说明]

已知对某载客车辆(Car)进行类建模，如图 5-1所示，其中类 Engine 表示发动机引擎，类 Wheel 表示车轮，类 Body 表示车身，类 Driver 表示司机，类 Passenger 表示乘客。

[C++代码]

const int (1) = 7; //定义最多载客数

const int MAX_WHEELS = 5; //定义最多轮胎数

class Body{ //此处代码省略 }; //车身类

class Passenger{ //此处代码省略 }; //乘客类

class Wheel{ //此处代码省略 }; //车轮类

class Driver{ //司机类

public:

string name; //表示第几路公交车司机

Driver(string driverName):name((2) ){}; //构造函数

};

class Engine{ //引擎类

public:

string engineNo; //引擎编号

Engine(string engineNo){ (3) -＞engineNo = engineNo; } //构造函数

};

class Car{ //汽车类

protected:

Engine * engine; Driver * driver; Body body;

Wheel * wheels[MAX_WHEELS]; Passenger * passengers[MAX_PASSENGERS];

public:

Car(Driver *driver){ //构造函数

this-＞driver = driver;

engine = new Engine("TX6536 型号引擎");

for (int index = 0; index ＜ MAX_WHEELS; index++){

wheels[index] = new Wheel();

}

for (int index = 0; index ＜ MAX_PASSENGERS; index++){

passengers[index] = NULL;

}

virtual ~Car(){ //析构函数

for (int index=0; index ＜ MAX_WHEELS; index++)

delete wheels[index];

delete (4) ;

}

int getPassengerNumber(){ //获取车上乘客数量

//此处代码省略

}

void getOnPassenger(Passenger * aPassenger ){ //乘客上车

//此处代码省略

}

void run(){ //开车

if(driver == NULL){ cout ＜＜ "司机尚未上车!"; return; }

//此处代码省略

}

};

void main(){

Driver driver("第五路公交车司机");

Car car((5) );

Passenger passengers[MAX_PASSENGERS];

for (int index = 0 ; index ＜ MAX_PASSENGERS; index ++) //乘客上车处理

car.getOnPassenger(&passengers[index]);

car.run();

}

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