题目内容
（请给出正确答案）
In C language，(58) is a collection of one or more variables，possibly of different types， grouped together under a single name for convenient handling.
A．a class
B．a structure
C．an array
D．a function
如果结果不匹配，请 联系老师 获取答案
更多“In C language，（58) is a collec…”相关的问题
The task at hand now is to(56)the programmers who still use yesterday's software technology to solve today's software problems. Object-oriented programming requires a new attitude toward problem(57). Problem(57)with computer system becomes more natural. Application can(58)be translated into(59). Although it is commonly believed that it will be easier to train new programmers to use object-oriented techniques than to(60)programmers who have substantial experience in applying conventional programming language constructs.
A．test
B．force
C．educate
D．touch
阅读下列说明和HTML文本，分析其中嵌入的JavaScript脚本，将应填入(n)处的语句写在对应栏内．
.jpg)
【说明】
在网页正中靠上显示一个固定的时钟，如图8-1所示。
HTML文本如下所示．
＜html＞
＜!-省略部分为HTML文本框＞
＜body nload="rad();counter(); ob();setNum();setlnterval('timer(),100); setlnterval('runClock ()',100)"＞
＜script. language="JavaScdpt"＞
var dot=60; //挂钟外边缘上的60个刻度
rads=(1);
function rad () {
for (i=1; i＜dot; i++) {//初始化刻度
if (document.all) rads[i]=new Array (eval('rad'+i).style,-100, -100);
else rads[i]: new Array (eval('document. rad'+i),-100,-100);
}
}
function setCircle() {//求外缘上60 个刻度的实际位置
for (i=1; i＜dot; i++) {
rads[i][0].left=rads[i][1]+pX-15;
if ((2))//检验是否是 NetScape4.x
rads[i][0].left+=10;
rads[i][0].top=rads[i][2]+pY-20;
}
}
function counter() {//设置外边缘上 60 个刻度相对于刻度中心的位置
for 0=1; i＜dot; i++) {
rad=Math. P1*(i/((dot-1)/2));
rads[i][1] = Math. sin(rad)*60;
rads[i][2] = -Math.cos(rad)*60;
}
setCircle();
}
pX=400;pY=150; //中心位置
obs=new Array(13); //储存秒针、分针、时针各组成部分位置的数组
function ob () {//初始化秒针、分针、时针各组成部分
for (i=0; i＜13; i++) {
if (document.all) obs[i]=new Array (eval('ob'+i), style,-100, 100);
else obs[i] = new Array (eval('document.ob'+i), -100, -100);
}
}
function cl(a,b,c){
if (document.all)//判断游览器种类，为真表示为IE
{
if (a!=0) b+= 1;
eval('c'+a+'.style.pixelTop='+(pY+(c-5)));
eval('o'+a+'.style.pixetLeft='+(pX+(b)));
}
else{
if (a!=0) b+=10;
eval('document.c'+a+'.top='+(pY+{c)));
eval('document.c'+a+'.left:'+(pX+(b))):
}
}
function runClock() {//求秒针、分针、时针各组成部分在屏幕上的实际位置
for (i=0; i＜13; i++) {
obs[i][0].left=(3);
obs[i][0].top=obs[i][2]+pY;
}
}
function timer() {
time = new Date ();//获取系统当前时间
sec=(4);
//计算秒针、分针、时针各自转动的角度
sec=Math. Pl*sec/30;
min=Math. Pl*time.getMinutes()/30;
hr =Math. Pl* ((time.getHours ()*60)+time, getMinutes ())/360;
//设定秒针各组成部分在屏幕上的相对位置
for ((5)) (
obs[i][1] = Math.sin(sec) * (44 - (i-1)*11) -16;
if (document.layers)obs[i][1]+=10;
obs[i][2] =-Math.cos(sec) * (44-(i-1)*11)-27;
}
//设定分针各组成部分在屏幕上的相对位置
for (i=6;i＜10;i++) {
obs[i][1]= Math.sin(min) * (40-(i-6)*10)-16;
if (document.layers)obs[i][l]+=10;
obs[i][2] = Math.cos(min) * (40 - (i-6)*10) -27;
}
//设定时针各组成部分在屏幕上的相对位置
for (i=10;i＜13;i++) {
obs[i][1] = Math.sin(hr) * (37 - (i- 10)*11)-16;
if (document.layers)obs[i][1]+=10;
ohs[i][2] =-Math.cos(hr) * (37- (i-10)*11)-27;
}
}
function setNum(){//设置并显示挂钟上的数字
cl (0, -67, -65);
cl (1,10,-51);
cl (2, 28, -33);
cl (3, 35,-8);
cl (4, 28, 17);
cl (5, 10, 35);
cl (6, -15, 42);
cl (7, -40, 35);
cl (8, -58, 17);
cl (9, -65, -8);
cl (10, -58, -33);
cl (11, -40, -51);
c1(12, -16, -56);
}
＜/script＞
A.58
B.56
C.45
D.24
试题（58）
对于提升磁盘I/O性能问题，以下表述正确的是（58） 。
（58）
A．数据库对象在物理设备上的合理分布能改善系统读写性能
B．磁盘镜像可以提高磁盘读写的速度
C．建议把数据库、回滚段、日志放在同一块设备上，以提高数据读写的性能
D．将磁盘升级到更大容量可提高磁盘I/O速度
以下程序用以删除字符串中所有的空格，请填空。
inculde ＜stdio.h＞
main()
{ char s[100]=(“our teacher teach c language!”);int I,j;
For(i=j=0;s[i]!=’’)
iF(s[i];s[i]!=’\0’) {s[j]=s[i];j ++}
s[j]=【 】
printF(“index=%d\n”,s-a);
}
（14 ）以下程序用以删除字符串所有的空格，请填空。
#include ＜stdio.h＞
main （）
{ char s[100]={ " Our teacher teach C language! " };int i,j;
for （i=j=0;s[i]!= ’ \0 ’ ;i++ ）
if （s[i]!= ‘ ’ ） {s[j]=s[i];j++;}
s[j]= 【 14 】
printf （" %s\n " ,s ） ;
}
设关系模式R，其中U={H，I，J，K，L}，若F={H→IJ，J→K，IJK→L，L→H，L→K)，则F的最小函数依赖集Fmin={(58)}。关系模式R的候选关键字有(59)个，R属于(60)。
A．H→I，H→J，J→K，IJK→L，L→H
B．H→I，H→J，J→K，IJ→L，L→H
C．H→I，H→J，J→K，IJ→L，J→K
D．H→I，J→K，IJ→L，L→H，L→K
Paragraph 1
My name is Brandon and I began Humans of New York in the summer of 2010.I thought it would be really cool to create a catalogue of New York City’s people, so I set out to photograph 10,000 New Yorkers and put their photos on a map.(1) I worked for several months with this goal in mind.(2) But along the way, I started collecting quotes and short stories from the people I met.Taken together, these pictures and captions became the subject of a blog.(3) Blogs are popular with all age groups.(4) With over eight million followers on social media, HONY now provides a worldwide audience with daily looks into the lives of strangers in New York City.It has also become a #1 NYT bestselling book.
Paragraph 2
Learning a second language can provide a deeper understanding of a foreign culture.Social habits that may not make sense to most outsiders might start to make more sense after a few vocabulary lessons.For example, I always wondered why my Dutch cousins rarely said “you’re welcome” after I said “thank you”.(1) My cousin can speak English but sometimes makes mistakes.(2) At first, I thought he was being rude, but when I learned more about his language, I realized that they don’t use “you’re welcome” the same way we do: in response to “thank you”.(3) They actually say something that translates to “If you please” when they offer you something.(4) This is one of the first things I learned about Dutch culture when I started to learn their language and it gave me a different perspective on the roles of host and guest since in Dutch the onus to be polite is on the host, and not the guest as it seems to be in English.
A.4小时67%，24小时76%
B.4小时2%，24小时4%
C.4小时25%，24小时40%
D.4小时62%，24小时58%
E.4小时5%，24小时20%
