To ()the CEO()ome of his work, the company decided to find for him two assis-tants.
A.reduce;/
B.relieve; of
C.decrease;/
D.cut down; on
A.reduce;/
B.relieve; of
C.decrease;/
D.cut down; on
The suggestion that the CEO () the prizes is' welcomed by all.
A.would present
B.present
C.presents
D.ought to present
(i)求出样本中的平均年薪和平均任期。
(ii)有多少位CEO尚处于担任CEO的第一年(就是说,ceoten=0)?最长的CEO任期是多少?
(ii)估计简单回归模型log(salary)=β0+β1ceoten+u,用通常的形式报告你的结果。多担任一年CEO,预计年薪增长(近似)的百分数是多少?
阅读以下说明和Java代码,将应填入(n)处的字句写在对应栏内。
[说明]
本程序的功能是给公司的员工Tom,Jack,Green增加薪水。三人的职位分别是programmer, Manager,CEO。
程序由6个类组成:WorkerTest是主类,programmer,Manager,CEO三个类,薪水增加的规则是 programmer的涨幅是5%;Manager的是10%;CEO也是Manager,但是它除了有Manager的涨幅,还有1000元的bonus。接口SalaryRaise提供了一个增加薪水的方法raise()。
[java程序]
public class WorkerTest {
public WorkerTest() {}
public static void main(String[] args) {
Programmer programmer = new Programmer("Tom" ,3000);
Manager manager = new Manager("Jack" ,4000);
CEO ceo = new CEO("Green" ,4000);
Worker [] worker = new Worker[3];
programmer, raise();
manager, raise();
ceo. raise();
worker[0] = programmer;
worker [1] = manager;
worker[2] = ceo;
for (int i = 0 ;i < worker, length; i + + ) {
System. out. prinfln (" Name:" + worker [i]. getName () +" \ tSalary:" + worker [i]. getSalary ());
public interface SalaryRaise { void raise(); }
public class Worker {
public String name;
public double (1);
public Worker() {}
public String getName() {return name;}
public void setName(String name) {this. name = name;}
public double getSalary() {return salary;}
public void setSalary(double salary) { this. salary = salary; }
}
public class Programmer extends Worker implements (2) {
public Programmer() {}
public void raise() {
double pets=0.05;
double sala = this. getSalary() * (1 + pers);
this. setSalary (sala);
public Programmer(Siring name, double salary) t
this. name = name;
this. salary = salary;
public class Manager extends (3) implements SalaryRaise {
public Manager() { }
public Manager(String name, double salary) {
this. name = name;
this. salary = salary;
}
public void raise() {
double pets = 0.1;
double sala = this. getSalary() * (1 + pers);
this. setSalary(sala);
}
}
public class CEO extends Manager implements SalaryRaise {
public CEO() {}
public CEO(String name,double salary) {
this. name = name;
this. salary = salary;
}
public void raise() {
double bonus = 1000;
(4);
double sala = this. getSalary();
(5);
this. setSalary(sala);
}
}
文件CEOSAL2.RAW包含了177位首席执行官的数据,并可用来考察企业业绩对CEO薪水的影响。
(i)估计一个将年薪与企业销售量和市场价值相联系的模型。让这个模型对每个自变量的变化都具有常弹性。以方程的形式写出结论。
(ii)在第(i)部分的模型中增加profits。为什么这个变量不能以对数形式进入模型?你会说这些企业业绩变量解释了CEO薪水波动中的大部分吗?
(iii)在第(ii)部分的模型中增加ceoten。保持其他条件不变,延长一年CEO任期,估计的百分比回报是什么?
(iv)求出变量log(mktval)和prots之间的样本相关系数。这些变量高度相关吗?这对OLS估计量有什么影响?
Observe that for the programmer, as for the chef, the urgency of the patron (顾客) may govern the scheduled completion of the task, but it cannot govern the actual completion. An ome?lette (煎鸡蛋) , promised in two minutes, may appear to be progressing nicely. But when it has not set in two minutes, the customer has two choices—waits or eats it raw. Software customers have had (71) choices.
Now I do not think software (72) have less inherent courage and firmness than chefs, nor than other engineering managers. But false (73 ) to match the patron' s desired date is much more common in our discipline than elsewhere in engineering. It is very (74) to make a vigorous, plausible, and job risking defense of an estimate that is derived by no quantitative method, supported by little data, and certified chiefly by the hunches of the managers.
Clearly two solutions are needed. We need to develop and publicize productivity figures, bug-incidence figures, estimating rules, and so on. The whole profession can only profit from (75) such data. Until estimating is on a sounder basis, individual managers will need to stiffen their backbones and defend their estimates with the assurance that their poor hunches are better than wish derived estimates.
(71)
A.no
B.the same
C.other
D.lots of
A.CEO
B. CFO
C. CIO
D. CKO