试把圆盘|z|<1保形映照成半平面Imω>0,并且将点-1,1, i映照成(1)∞, 0, 1;或(2)-1, 0,1.
设f(u)为连续函数,Ω为圆柱面x2+y=x与平面z=0和z=1围成的圆柱体.试将化为一重积分[定积分]
有如下程序:
#include
using namespace std;
class Complex
{
double re, im;
public:
Complex(double r, double i):re(r), im(i){}
double real() const{return re;}
double image() const{return im;}
Complex& operator +=(Complex a)
{
re += a.re;
im += a.im;
return *this;
}
};
ostream &operator<<(ostream& s,const Complex& z)
{
return s<<'('<
}
int main()
{
Complex x(1, -2), y(2, 3);
cout<<(x += y)<
return 0;
}
执行这个程序的输出结果是
A . (1, -2)
B . (2, 3)
C . (3, 5)
D . (3, 1)
A.(1,-2)
B.(2,3)
C.(3,5)
D.(3,1)
A.(1,-2)
B.(2,3)
C.(3,5)
D.(3,1)
图4-13所示偏心圆盘凸轮机构,圆盘半径为R,试在画中画出:
(1)理论廓线;
(2)基圆;
(3)偏距圆;
(4)图示位置的推杆位移;
(5)试写出推杆位移的解析表达式.
A.(1,-2)
B.(2,3)
C.(3,5)
D.(3,1)
设点A(1,0,0)与B(0,1,1),线段绕Oz轴旋转一周所成的旋转曲面为S,求由S与两平面z=0和z=1所围成立体的体积.
题11-4图(a)所示正六边形截面,边长为a,z轴为水平形心轴,试计算截面的惯性矩Iz,与抗弯截面系数Wz.