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The system is()but it needs some fine-tuning.

The system is()but it needs some fine-tuning.

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更多“The system is()but it needs so…”相关的问题
第1题
The basic units of a computer sysiem are as follows: () .A.CPU, memory and diskB.CPU, inpu

The basic units of a computer sysiem are as follows: () .

A.CPU, memory and disk

B.CPU, input and output

C.CPU, memory and ALU

D.CPU, memory and I/O system

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第2题
● (75) are designed to manage large bodies of information. (75)A. I/O ports B. Printers C

● (75) are designed to manage large bodies of information.

(75)

A. I/O ports

B. Printers

C. Database system

D. Keyboards

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第3题
Applications put computers to pratical business (1), but below the (2) it's the heart of a

Applications put computers to pratical business (1), but below the (2) it's the heart of an operating system—the kernel that provides the technical wizardry to juggle multiple program, connect to networks and store (3) . A traditional kernal provides all the functions for applications. The kemal (4) memory, I/O devices and parcels out processor time.

The kernel also supports security and fault (5) , which is the ablity to recover automatically when parts of the system fail.

A.used

B.use

C.apply

D.applied

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第4题
下列程序的输出的结果是______。public class exl6{ public static void main(String[]args){ int

下列程序的输出的结果是______。 public class exl6 { public static void main(String[] args) { int j=10; for(int i=0;i<3;i++) { j-=i+1; switch (j){ case 3: break; case 5: break; case 8: break; default: j=0;break; } } System,out.println(j); } }

A.5

B.3

C.8

D.0

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第5题
All computers need some sort of(71)(OS). Tile majority of modem home computers use some fo

All computers need some sort of(71)(OS). Tile majority of modem home computers use some form. of Microsofts OS. The original Microsoft OS was called DOS though most computers use Windows. Windows comes in various versions beginning with(72)x then 95, 98, ME and currently XP. A few computers use IBMs O/SApples Mac uses their own OS beginning with OS I though most modem Macs use version x or x. Apples latest version is OS 10.x. In the past large companies and institutions would have an OS design exclusively for them but as the Commercial OS become more sophisticated the benefits of this practice is becoming less apparent. Some computer professionals,(73)(ISP)and(74)computer users use an OS such as UNIX(or a variant such as Linux), Windows NT or 2000(Win2k)or one of the other network or(75)based OS.

A.Operated System

B.Operated System

C.Operating System

D.Operation System

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第6题
下列给定程序中,函数p roc的功能是:先将字符串s 中的字符按顺序存放到t中,然后把S中的字符按正序
连接到t的后面。例如,当s中的字符串为WXYZ时,则t中的字符串应为WXYZWXYZ。 请改正程序中的错误,使它能得出正确的结果。 注意:不要改动main函数,不得增行或删行,也不得更改程序的结构。 试题程序: include<stdlib.h> include<conio.h> include<stdio.h> include<string.h> void proc(char*s,char*t) { int i,s1; s1=strlen(s); for(i=0;i<s1;i++) //****found**** t[i]=s[s1]; for(i=0;i<s1;i++) t[s1+i]一s[i]; t[2*s1]=\O0; } void main { char s[100],t[100]; system("CLS"); print{("\nPlease enter string s:"); scanf("%s",s); proc(s,t); printf("The result is:%s\n",t); }

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第7题
When the system upon which a transport entity is running fails and subsequently restarts,
the(66)information of all active connections is lost. The affected connections become half-open, as the side that did not fail does not yet realize the problem.The still active side of a half-open connection can close the connection using a(67)timer. This timer measures the time the transport machine will continue to await an(68)of a transmitted segment after the segment has been retransmitted the maximum number of times. When the timer(69), the transport entity assumes that either the other transport entity or the intervening network has failed. As a result, the timer closes the connection, and signals an abnormal close to the TS user.In the event that a transport entity fails and quickly restarts, half-open connections can be terminated more quickly by the use of the RST segment. The failed side returns an RST i to every segment i that it receives. When the RST i reaches the other side, it must be checked for validity based on the(70)number i, as the RST could be in response to an old segment. If the reset is valid, the transport entity performs an abnormal termination.

A.data

B.state

C.signal

D.control

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第8题
●Applications put computers to practical business (67) ,but below the (68) it's the heart

●Applications put computers to practical business (67) ,but below the (68) it's the heart of an operating system-the kernel-that provides the technical wizardry to juggle multiple program,connect to networks and store (69) .

A traditional kernel provides all the functions for applications.The kernel (70) memory,I/O devices and parcels out processor time.

The kernel also supports security and fault (71) ,which is the ability to recover automatically when parts of the system fail.

(67) A.used

B.use

C.apply

D.applied

(68) A.earth

B.bottom

C.table

D.surface

(69) A.graphics

B.data

C.text

D.image

(70) A.manages

B.manage

C.managed

D.managing

(71) A.error

B.question

C.tolerance

D.problem

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第9题
when the system upon which a transport entity is running fails and subsequently reatarts,t
he()information of all active connections is lost.the affected connections become half-open,as the side that did not fail does not yet realize the promble. The still active side of a half-open connections using a()timer.this timer measures the time transport machine will continue to await an()of a transmitted segment after the segment has been retransmitted the maximum number of times.when the timer(),the transport entity assumes that either the other transport entity or the intervening network has failed.as a result,the timer closes the connection,and signals an abnormal close to the TS user. In the event that a transport entity fails and quickly restart,half-open connections can be teminated more quickly by the use of the RST segment.the failed side returns an RST I to every segment I that it receives.when the RST I reaches the other side,it must be checked for validity dased on the ()number I,as the RST could be in response to an old segment .if the reset is valid,the transport entity performs an abnormal termination.

A.data B.state C.signal D.control A.give-up B.abandon C.quit D.connection A.reset B.acknowledgment C.sequence D.synchroizer A.stops B.restarts C.expires D.abandons A.sequence B.acknowledgment C.connection D.message

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第10题
As mentioned above, C imposes relatively few built - in ways of doing things on the progra
m- mer. Some common tasks, such as manipulating(66),(67), and doing(68)(I/O), are performed by calling on library functions. Other tasks which you might want to do, such as creating or listing directories, or interacting with a mouse, or displaying windows or other(69)elements, or doing color graphics, are not defined by the C language at all. You can do these things from a C program, of course, but you will be calling on services which are peculiar to your programming environment(70), processor, and operating system)and which are not defined by the C standard. Since this course is about portable C programming, it will also be steering clear of facilities not provided in all C environments.

A.lines

B.strings

C.threads

D.routes

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第11题
阅读以下说明和C程序,将应填入(n)处的字句写在对应栏内。【说明】 下面的程序按照以下规则输出给定

阅读以下说明和C程序,将应填入(n)处的字句写在对应栏内。

【说明】

下面的程序按照以下规则输出给定名词的复数形式。

a.若名词以“y”结尾,则删除y并添加“ies”;

b.若名词以“s”、“ch”或“sh”结尾,则添加“es”;

c.其他所有情况,直接添加“s”。

【C程序】

include <stdio.h>

include <string.h>

char*plural(char *word)

{

int n;

char *pstr;

n=strlen(word); /*求给定单词的长度*/

pstr=(char*)malloc(n+3);/*申请给定单词的复数形式存储空间*/

if (!pstr||n<2)

return NULL;

strcpy(pstr,word); /*复制给定单词*/

if ((1))

{

pstr[n-1]='i';pstr[n] ='e';pstr[n+1]='s';(2);

}

else

if(pstr[n-1]=='s'| |pstr[n-1]=='h'&&((3)))

{

pstr[n]='e';pstr[n+1]='s';pstr[n+2]='\0';

}

else

{ pstr[n]='s';pstr[n+1]='\0';)

(4);

}

main()

{ int i; char *ps;

char wc[9][10]=

{"chair","dairy","boss","circus","fly","dog","church","clue","dish");

for(i = 0;i<9; i++) {

ps= (5) ;

printf("%s: %s\n",wc[i],ps); /*输出单词及其复数形式*/

free(ps); /*释放空间*/

}

system("pause");

}

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