The phrase “ the students in Class Two” is a()construction.
A.endocentric
B.exocentric
C.hypotactic
D.paratactic
A.endocentric
B.exocentric
C.hypotactic
D.paratactic
A.student是结构体变量
B.stu是typeStudent类型的变量
C.可以用stu定义结构体变量
D.student是派生类型,stu是结构体变量
设有关系模式:student (sno,sname,age,dept),现利用命令: CREATE VIEW stu AS SELECT*FROM student WHERE dept="cs"WITH CHECK OPTION 创建了一个视图。则以下SQL命令中能正确执行的是()。
A.UPDATE stu SET dept="maths"
B.UPDATE stu SET dept="maths" WHERE age>=20
C.INSERT INTO stu VALUES("2004001","John",30,"cs")
D.INSERT INTO stu VALUES("2004001","John",50,"maths")
A.p++->num
B.(p++)->age
C.(*++p).num
D.(*p).num
程序: #include <stdio.h> #include <string.h> typedef struct{char name[9];char sex;float score[2]}STU; STU f(STU A) {STU b={"Zhao",'m',85.0,90.0}; int i; strcpy(a.name,b.namC) ; a.sex=b.sex; for(i=0;i<2;i++) a.score[i]=b.score[i]; return a; } main() {STU c={"Qian",'f',95.0,92.0},d; d=f(C) ; pintf("%s,%c,%2.of.%2.of\n",d.name,d.sex,d.score[0],&score[1]); } 程序的运行结果是()。
A.Qian,f,95,92
B.Qian,m,85,90
C.Zhao,m,85,90
D.Zhao,C95,92
设有关系模式:student(sno, sname, age, dept),现利用命令: CREATE VIEW stu AS SELECT *FROM student WHERE dept="cs"WITH CHECK OPTION 创建了一个视图。则以下SQl命令中能正确执行的是
A.UPDATE stu SET dept="maths"
B.UPDATE stu SET dept="maths"WHERE age>=20
C.INSERT INTO stu VALUES ("2004001", "John", 30, "cs")
D.INSERT INTO stu VALUES ("2004001", "John", 50, "maths")
若有以下定义的语句
struct student
{ int age;
int num; };
struct student stu[3]={{1001,20},{1002,19},{1003,21}};
main()
{ struct student *p;
p=stu;
… }
则以下不正确的引用是
A.(p++)->num
B.p++
C.(*p).num
D.P=&stu.age.
A.structstudentstu[2]={1,"zhangsan",2,"lisi"}
B. struct student stu[2]={1, "zhangsan",2,"li si"}
C. struct student stu[2]={{1,"zhangsan"},{2,"li si"}};
D. struct stu[]={{1,"zhangsan"},{2,"li si"}}
有如下语句: Type Student Name As String Age As Integer Sex As String End Type Dim Stu As Student With Stu .Name="张红" .Age=22 .Sex="女" End With 执行Print Stu.Age语句后的结果是
A.张红
B.22
C.“女”
D.Age
有以下程序: struct STU {char name[10];int num;float TotalScore;}; void f(struct STU *p) {struct STU s[2]={{"SunDan",20044,550},{"Penghua",20045,537}},*q=s; ++p;++q; *p=*q; } main() {struct STU s[3]={{"YangSan",20041,703},{"LiSiGuo",20042,580}}; f(s); printf("%s%d%3.0f\n",s[1].name,s[1].num,s[1].TotalScore); } 程序运行后的输出结果是 ______。
A.SunDan 20044 550
B.Penghua 20045 537
C.LiSiGuo 20042 580
D.SunDan 20041 703